Election in Pennsylvania
1864 United States presidential election in Pennsylvania
|
|
| | | Nominee | Abraham Lincoln | George B. McClellan | | Party | National Union | Democratic | Home state | Illinois | New Jersey | Running mate | Andrew Johnson | George H. Pendleton | Electoral vote | 26 | 0 | Popular vote | 296,391 | 276,316 | Percentage | 51.75% | 48.25% | |
County Results Lincoln 50-60% 60-70% 70-80% | McClellan 50-60% 60-70% 70-80% 80-90% | |
President before election Abraham Lincoln Republican | Elected President Abraham Lincoln National Union | |
Elections in Pennsylvania |
---|
|
|
|
|
|
|
|
|
|
Government |
|
The 1864 United States presidential election in Pennsylvania took place on November 8, 1864, as part of the 1864 United States presidential election. Voters chose 26 representatives, or electors to the Electoral College, who voted for president and vice president.
Pennsylvania voted for the National Union candidate, incumbent Republican President Abraham Lincoln and his running mate Andrew Johnson. They defeated the Democratic candidate, George B. McClellan and his running mate George H. Pendleton. Lincoln won the state by a narrow margin of 3.5%.
Results
1864 United States presidential election in Pennsylvania[1] |
Party | Candidate | Votes | Percentage | Electoral votes |
| National Union | Abraham Lincoln (incumbent) | 296,391 | 51.75% | 26 |
| Democratic | George B. McClellan | 276,316 | 48.25% | 0 |
Totals | 572,707 | 100.0% | 26 |
See also
References
- ^ "1864 Presidential General Election Results - Pennsylvania". U.S. Election Atlas. Retrieved August 3, 2012.