1840 United States presidential election in Louisiana

1840 United States presidential election in Louisiana

← 1836 October 30 – December 2, 1840 1844 →

Nominee William Henry Harrison Martin Van Buren Party Whig Democratic Home state Ohio New York Running mate John Tyler none Electoral vote 5 0 Popular vote 11,296 7,616 Percentage 59.73% 40.27%

President before election Martin Van Buren Democratic Elected President William Henry Harrison Whig

Elections in Louisiana
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The 1840 United States presidential election in Louisiana took place between October 30 and December 2, 1840, as part of the 1840 United States presidential election. Voters chose five representatives, or electors to the Electoral College, who voted for President and Vice President.

Louisiana voted for the Whig candidate, William Henry Harrison, over Democratic candidate Martin Van Buren. Harrison won Louisiana by a margin of 19.46%.

With 59.73% of the popular vote, Louisiana would prove to be Harrison's fourth strongest state after Kentucky, Vermont and Rhode Island.^[1]

Results

See also

• United States presidential elections in Louisiana

References