Election in Georgia
1796 United States presidential election in Georgia
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| |  |  | | Nominee | Thomas Jefferson | John Adams | | | Party | Democratic-Republican | Federalist | | Home state | Virginia | Massachusetts | | Running mate | Aaron Burr | Thomas Pinckney | | Electoral vote | 4 | 0 | | Popular vote | 19,132 | 8,432 | | Percentage | 68.44% | 30.16% | |
 County Results [1] | Jefferson 50–60% 60–70% 70–80% 80–90% 90-100% | Adams 50–60% 60–90% 90-100% | No Data | Yazoo lands | |
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The 1796 United States presidential election in Georgia took place on 4 November 1796, as part of the 1796 United States presidential election. The voters chose four representatives, or electors, through plurality block voting to the Electoral College. These electors then voted for President and vice president.[1]
Out of 51 elector candidates, four Democratic-Republican electors were elected who then voted for Thomas Jefferson over the Federalist candidate and incumbent vice President John Adams. The electoral votes for vice president were however not cast for Jefferson's running mate Aaron Burr, but for George Clinton from New York.[2][1]
Results
Composite Vote
Elector Vote
See also
References
- ^ a b c d e "A New Nation Votes". elections.lib.tufts.edu. Retrieved February 21, 2024.
- ^ "1796 Presidential General Election Results". U.S. Election Atlas. Retrieved July 10, 2023.
- ^ "Our Campaigns - GA US President Race - Nov 00, 1796". www.ourcampaigns.com. Retrieved February 21, 2024.
- ^ Dubin, Michael J. (2009). United States Presidential Elections, 1788-1860: The Official Results by County and State. McFarland. pp. 6, 8. ISBN 9780786454518.
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- See also
- Presidential elections
- Senate elections
- House elections
- Gubernatorial elections
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